Hello levend,
here some more hints to bring up your T1000S...
(By the way, what's your real given name?
)
1. Lithium battery / NiMh accu
The Li-battery only buffers the customer memory (one static RAM IC) which contains the identification and some other programmings.
Other memory Chips and RTC are buffered by the NiMh-accu....
So, if you didn't disconnect the battery substitute yet, you can try to read the identification:
Switch the machine to programm mode (P-button+paper feed), then type "22"
(This function works without service plug)
If an identification is stored the result looks like this:
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Kennung.jpg
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When replacing the batteries, be sure to check whether the ON/OFF-switch works reliably.
Sometimes corrosive vapors from the batteries cause malfunctions.
2. Service plug
Here my solution:
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SES01.jpg
SES02.jpg
SES04.jpg
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3. Timer Function
Your T1000S has a switch with a clock symbol on the left switchboard.
This switch usually is implemented if the machine was used with permanent connection and represents a timer-function.
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Zeitschalter.jpg
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Translation:
Timer ON/OFF
With permanent connection (fixed line to a remote station) the timer switches the T1000 S
off if within a certain time neither characters are sent nor be received.
The indicator lights up when the timer is turned off, i.e. when the connection remains.
So, don't push the timer switch and wait a while, machine should switch off after about 3 to 6 minutes.
4. Line interface, connection
First of all here some pictures to understand single an double current connection:
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Einfach-Doppelstrom_1.jpg
Einfach-Doppelstrom_2.jpg
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In other words, at single current the character cuts of the loop current, at double current it changes polarity.
As you can see in the circuit diagram, receiving and transmitting loops are totally separated, i.e. when using double current you always need two wire pairs! I think they should appear at pin 1+2 (Rx) and 3+4 (Tx) of the ADoS8, or the other way round, I dont know!
And, if it is a double current interface, you should mesuare a voltage of about 60V at either pin 1+2 or pin 3+4!
In this respect, the behavior of the interface is a bit strange because a current is flowing, when the voltage is applied to pin 1+4.
Can you write with printing when the 7,8 mA currentflows?
From my point of view it looks like a single current interface, because if muliplying your values by 5 you get following results:
24V x 5 = 120V
0,8mA x 5 = 4mA
7,8mA x 5 = 39mA
And these are the values of a single current interface (120V, 5mA standby-current and 40mA working current)...
Increase voltage or standby-current carefully to 4 or at least 5mA, than change polarity and wach what happens!
Best regards